Question

se technology to find the P-value for the hypothesis test described below.

The claim is that for a smartphone carrier's data speeds at airports, the mean is

muμequals=16.00

Mbps. The sample size is

nequals=14

and the test statistic is

tequals=negative −2.404.

P-valueequals=nothing

(Round to three decimal places as needed.)

se technology to find the P-value for the hypothesis test described below.

The claim is that for a smartphone carrier's data speeds at airports, the mean is

muμequals=16.0016.00

Mbps. The sample size is

nequals=1414

and the test statistic is

tequals=negative 2.404−2.404.

P-valueequals=nothing

(Round to three decimal places as needed.)

se technology to find the P-value for the hypothesis test described below.

The claim is that for a smartphone carrier's data speeds at airports, the mean is

muμequals=16.0016.00

Mbps. The sample size is

nequals=1414

and the test statistic is

tequals=negative 2.404−2.404.

P-valueequals=nothing

(Round to three decimal places as needed.)

se technology to find the P-value for the hypothesis test described below.

The claim is that for a smartphone carrier's data speeds at airports, the mean is

muμequals=16.00

Mbps. The sample size is

nequals=14

and the test statistic is

tequals=negative −2.404.

P-valueequals=nothing

(Round to three decimal places as needed.)

Answer #1

Solution :

The null and alternative hypotheses are as follows :

Mbps

Mbps

The value of the test statistic is, t = -2.404

Sample size (n) = 14

Degrees of freedom = (n - 1) = (14 - 1) = 13

Since, the test is two-tailed test, therefore we shall obtain the two-tailed p-value for the test statistic. The two-tailed p-value is given as follows :

p-value = 2.P(T > |t|)

We have, |t| = 2.404

p-value = 2.P(T > 2.404)

Using R software we get, 2.P(T > 2.404) = 0.032

Hence, p-value = 0.032

**The p-value is 0.032**.

se technology to find the P-value for the hypothesis test
described below.
The claim is that for a smartphone carrier's data speeds at
airports, the mean is
muμequals=12.00
Mbps. The sample size is
nequals=17
and the test statistic is
tequals=1.118
P-valueequals= 0.025
(Round to three decimal places as needed.)

Use technology to find the P-value for the hypothesis test
described below. The claim is that for a smartphone carrier's data
speeds at airports, the mean is muμequals=17.00Mbps. The sample
size is nequals=26 and the test statistic is tequals=2.336

Use technology to find the P-value for the hypothesis test
described below. The claim is that for a smartphone carrier's data
speeds at airports, the mean is muequals11.00 Mbps. The sample
size is nequals22 and the test statistic is tequals1.797.

use technology to find the P- value for the hypothesis
test described below
the claim is that for a smartphone carrier's data speed at
airports, the mean is mu =19.00 mbps. the sample size n = 14 and
the test statistic is t= 1.118.
how is this entered into a TI 84

Use
technology to find the P-value for the hypothesis test described
below.
The claim is that for a smartphone carrier’s data speeds at
airports, the mean is u= 14 mbps. The sample size is n=18 and the
test statistic is t= -2.055.

Use technology to find the? P-value for the hypothesis test
described below.
The claim is that for 12 AM body? temperatures, the mean is
mu?greater than>98.698.6degrees°F.
The sample size is
nequals=88
and the test statistic is
tequals=1.4641.464.

The claim is that for a smartphone carrier's data speeds at
airports, the mean is μ=18.00 Mbps. The sample size is n=1717 and
the test statistic is t=−1.976.

The display provided from technology available below results
from using data for a smartphone carrier's data speeds at airports
to test the claim that they are from a population having a mean
less than 6.00 Mbps. Conduct the hypothesis test using these
results. Use a 0.050 significance level. Identify the null and
alternative hypotheses, test statistic, P-value, and state the
final conclusion that addresses the original claim.
null? hypotheses?
z= ??
p-vale?
conclusion? evidence or not enough evidence?

The display provided from technology available below results
from using data for a smartphone carrier's data speeds at airports
to test the claim that they are from a population having a mean
less than
4.00
Mbps. Conduct the hypothesis test using these results. Use a
0.05
significance level. Identify the null and alternative
hypotheses, test statistic, P-value, and state the final
conclusion that addresses the original claim.
LOADING...
Click the icon to view the display from technology.
Assuming all conditions...

Test the hypothesis using the P-value approach. Be sure to
verify the requirements of the test.
Upper H0:
pequals=0.8
versus
Upper 1H :p
greater than>0.80
nequals=250
xequals=205
alphaαequals=0.05
Is
np 0 left parenthesis 1 minus p 0 right
parenthesisnp01−p0greater than or equals≥10?
Use technology to find the P-value.
P-valueequals=nothing
(Round to three decimal places as needed.)

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