Question

The amount of time a bank teller spends with each customer has a population mean μ=...

The amount of time a bank teller spends with each customer has a population mean μ= 3.10 and a standard deviation σ =0.40 minute. If you select a random sample of 20 customers

REQUIRED

  1. What is the probability that the mean time spent per customer is at least 5 minutes?

  2. There is an 85% chance that the sample mean is below how many minutes?

  3. What assumption must you make in order to solve (a) and (b)?

  4. If you select a random sample of 75 customers, there is an 85% chance that the sample mean is below how many minutes?

  5. Is the sample selected in section ( d ) normally distributed ? Why?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Complete solution for the problem can be found in the images below with all the necessary steps.
Do give a thumbs up if you liked the solution. Thank You :)

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The amount of time a bank teller spends with each customer has a population​ mean, mu​,...
The amount of time a bank teller spends with each customer has a population​ mean, mu​, of 2.80 minutes and a standard​ deviation, sigma​, of 0.50 minute. b. If you select a random sample of 16 ​customers, there is an 85​% chance that the sample mean is less than how many​ minutes?
The amount of time a bank teller spends with each customer has a population​ mean, mu​,...
The amount of time a bank teller spends with each customer has a population​ mean, mu​, of 2.80 minutes and a standard​ deviation, sigma​, of 0.50 minute. d. If you select a random sample of 100 ​customers, there is an 85​% chance that the sample mean is less than how many​ minutes?
The amount of time a bank teller spends with each customer has a population​ mean, muμ​,...
The amount of time a bank teller spends with each customer has a population​ mean, muμ​, of 2.902.90 minutes and a standard​ deviation, sigmaσ​, of 0.500.50 minute. Complete parts​ (a) through​ (d). a. If you select a random sample of 1616 ​customers, what is the probability that the mean time spent per customer is at least 2.8 ​minutes? . 7881.7881 ​(Round to four decimal places as​ needed.)b. If you select a random sample of 1616 ​customers, there is an 84​%...
Assume the standard deviation of time spent preparing for classes is 4 hours. If you select...
Assume the standard deviation of time spent preparing for classes is 4 hours. If you select a random sample of 16 students, a. what is the probability that the mean time spent preparing for classes is at least 14 hours per week? b. there is an 85% chance that the sample mean is less than how many hours per week? c. what assumption must you make in order to solve (a) and (b)? d. if you select a random sample...
The amount of time that a customer spends waiting at an airport check-in counter is a...
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.1 minutes and standard deviation 1.6 minutes. Suppose that a random sample of n=50 customers is observed. Find the probability that the average time waiting in line for these customers is (a) Less than 10 minutes (b) Between 5 and 10 minutes (c) Less than 6 minutes Round your answers to four decimal places (e.g. 0.9876).
The amount of time travellers at an airport spend with customs officers has a mean of  μ...
The amount of time travellers at an airport spend with customs officers has a mean of  μ =31 μ =31 seconds and a standard deviation of  σ =14 σ =14 seconds. For a random sample of 35 travellers, what is the probability that their mean time spent with customs officers will be: a) Over 30 seconds? b) Under 35 seconds? c) Under 30 seconds or over 35 seconds?
Question 1: Your analytics team tells you that amount of time a typical customer spends in...
Question 1: Your analytics team tells you that amount of time a typical customer spends in a coffee shop is normally distributed with mean (?) 10 minutes and standard deviation (?) of 3 minutes. What proportion of customers spend less than 5 minutes in the coffee shop? Question 2: Your analytics team tells you that a coffee customer spending in the store is normally distributed with mean (?) $5 dollars and a standard deviation (?) $2 dollars. What is the...
Full-time college students report spending a mean of 25hours per week on academic? activities, both inside...
Full-time college students report spending a mean of 25hours per week on academic? activities, both inside and outside the classroom. Assume the standard deviation of time spent on academic activities is 4 hours. Complete parts? (a) through? (d) below. a. If you select a random sample of 25 ?full-time college? students, what is the probability that the mean time spent on academic activities is at least 24 hours per? week? ?(Round to four decimal places as? needed.) b. If you...
Suppose a bank manager has developed a new system to reduce customer wait time at branches...
Suppose a bank manager has developed a new system to reduce customer wait time at branches for teller services. She obtains a sample of 100 customer wait times, and calculates the sample mean wait time to be 5.65 minutes. She knows that the population standard deviation is 1.20 minutes. Suppose the bank manager wants to ensure that the margin of error of her 95% confidence interval is no more than 0.20 minutes. How large a sample should she obtain? C.I....
A bank claims that the mean waiting time in line is less than 1.7 minutes. A...
A bank claims that the mean waiting time in line is less than 1.7 minutes. A random sample of 20 customers has a mean of 1.5 minutes with a standard deviation of 0.8 minute. If α = 0.05, test the bank's claim using p-values.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT