About 10% of users do not close Windows properly. Suppose that
Windows is installed in a public library that is used by random
people in a random order:
(Hint: you can answer these questions by applying one of the
distributions that you learned this week.)
In this case, we have only two outcomes ie closing windows properly or not.
Since it is only one of teh two possible outcomes, it is a Binomial distribution. Here, we have p=0.1 (problity of not closing the windows properly)
Since for a Binomial distribution, we know that the mean is np, we have on an average, n*0.1=0.1n users don't close teh windows properly.
It is given that on one day, there are 25 users. Hence the number of users don't close Windows =np=25*0.1=2.5 or 3 users don't close te windows and this implies that 22 users shut teh windows properly.
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