**URGENT**
What is the probability that the drives use no more than 7.0 gallons of gasoline per week?
(show sketch in your answer)
Solution :
Given that ,
mean = = 8.2
standard deviation = = 0.47
P(x 7.0)
= P[(x - ) / (7.0 - 8.2) / 0.47]
= P(z -2.5532)
= 0.0053
Probability = 0.0053
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