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If a random sample of 41 items produces x = 128.4 and s = 20.6, what...

If a random sample of 41 items produces x = 128.4 and s = 20.6, what is the 98% confidence interval for μ? Assume x is normally distributed for the population. What is the point estimate?

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Answer #1

128.4   2.423 ( 20.6 / 41 )

128.4   7.795

(120.60 , 136.20 )

At 98 %, CI for Population Mean is (120.60 , 136.20 )

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Point Estimate = x bar = 128.4

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