Question

Close Friends: The 2004 General Social Survey (GSS) interviewed a random sample of adult Americans. For...

Close Friends: The 2004 General Social Survey (GSS) interviewed a random sample of adult Americans. For one question the interviewer asked: “From time to time, most people discuss important matters with other people. Looking back over the last six months – who are the people with whom you discussed matters important to you? Just tell me their first names or initials.” The interviewer then recorded how many names or initials the respondent mentioned. Results are tallied in the following table: Number of Close Friends 0 1 2 3 4 5 6 Total Count (number of respondents) 397 281 263 232 128 96 70 1467 Answer the following questions in complete sentences. When showing work, calculator commands with correct parameters is sufficient. (You do not have to include keystrokes).

d. Which two of the following are reasonable interpretations of this confidence interval and its confidence level.

1. You can be 90% confident that then mean number of close friends in the population is between the endpoints of this interval.

2. Ninety percent of all people in this sample reported a number of close friends within this interval.

3. If you took another sample of 1467 people, there is a 90% chance that its sample mean would fall within this interval.

4. If you repeatedly took random samples of 1467 people, this interval would contain 90% of your sample means in the long run.

5. If you repeatedly took random samples of 1467 people and constructed tintervals in this same manner, 90% of the intervals in the long run would include the population mean number of close friends.

6. This interval captures the number of close friends for 90% of the people in the population.

e. Choose one of the four incorrect interpretations in part d and explain why it is incorrect.

f. Describe how the interval would change if all else remained the same except the following change was made: 1. The sample size was larger 2. The sample mean was larger 3. The sample values were less spread out 4. Every person in the sample reported one more close friend Now, from this same data g. Produce and interpret a 90% confidence interval for the population proportion of people who would report having 0 close friends. h. What information is gained in reporting a t-interval for the population mean rather than for these intervals?

Homework Answers

Answer #1

d) At 90% confidence interval and df = 1467-1=1466, critical value, t* = 1.646

90% confidence interval for mean

Answer 1. You can be 90% confident that then mean number of close friends in the population is between the 1.911 and 2.063 of this interval.

4. If you repeatedly took random samples of 1467 people, this interval would contain 90% of your sample means in the long run.

e) 2. Ninety percent of all people in this sample reported a number of close friends within this interval.

Its is incorrect because it interval does not make interpratation about the sample.

f) 1. The sample size was larger : the confidence interval will decrease.

2. The sample mean was larger : the confidence interval will shift. but will will remain same.

3. The sample values were less spread out : the confidence interval will decrease.

4. Every person in the sample reported one more close friend :  the confidence interval will remain same.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Earlier, we considered data from the GSS on numbers of close friends people reported having. The...
Earlier, we considered data from the GSS on numbers of close friends people reported having. The mean for this variable is 7.44, with a standard deviation of 10.98. Let's say that you decide to use the GSS data to test whether people who live in rural areas have a different mean number of friends than does the overall GSS sample. Again, treat the overall GSS sample as the entire population of interest. Let's say you select 40 people living in...
The General Social Survey (GSS) is a survey of approximately 2000 adults conducted each year since...
The General Social Survey (GSS) is a survey of approximately 2000 adults conducted each year since 1972, for a total of 38,000 participants. During several years of the GSS, participants were asked how many close friends they have. The mean for this variable is 7.44 friends, with a standard deviation of 10.98. The median is 5.00, and the mode is 4.00. 4. Now pretend you randomly selected a sample of 80 people from this population. Using symbolic notation, calculate the...
We are considering data from the GSS on numbers of close friends people reported having. The...
We are considering data from the GSS on numbers of close friends people reported having. The mean for this variable is 7.44, with a standard deviation of 10.98. Let's say that you decide to use the GSS data to test whether people who live in rural areas have a different mean number of friends than does the overall GSS sample. Again, treat the overall GSS sample as the entire population of interest. Let's say that you select 40 people living...
Suppose that 300 statistics students each took a random sample (with replacement) of 50 students at...
Suppose that 300 statistics students each took a random sample (with replacement) of 50 students at their college and recorded the ages of the students in their sample. Then each student used his or her data to calculate a 90 % the confidence interval for the mean age of all students at the college. How many of the 300 intervals would you expect to capture the true population mean age, and how many would you expect not to capture the...
he 2012 General Social Survey asked, “What do you think the ideal number of childrenfor a...
he 2012 General Social Survey asked, “What do you think the ideal number of childrenfor a family to have?” The 590 females who gave a numeric response from 0 to 6 had a median of 2,mean of ̄x= 2.56, and standard deviation ofs= 0.84.a) Two assumptions of confidence interval is : random sample, normal population. General SocialSurvey used a random sample. Do you think this population distribution of ”ideal number ofchildren” satisfy the normality assumption? Why or why not?b) What...
A 2004 Gallup survey interviewed a nationally representative random sample of 500 teenagers aged 13 to...
A 2004 Gallup survey interviewed a nationally representative random sample of 500 teenagers aged 13 to 17; 51 acknowledged having smoked in the past week. (a) What parameter are we interested in? n, the number of teenagers in the sample p, the proportion of the U.S. population who are aged 13 to 17 p, the proportion of teenagers aged 13 to 17 who acknowledge having smoked in the week before their interview n, the number of people who smoke Correct:...
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is...
Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bottle is determined. Let μ denote the average alcohol content for the population of all bottles of the brand under study. Suppose that the resulting 95% confidence interval is (7.6, 9.2). (a) Would a 90% confidence interval calculated from this same sample have been narrower or wider than the given interval? Explain your reasoning. The 90% would...
Software analysis of the salaries of a random sample of 251 teachers in a particular state...
Software analysis of the salaries of a random sample of 251 teachers in a particular state produced the confidence interval shown below. Determine if the following conclusions are correct. If​ not, state what is wrong with the conclusion. Complete parts a through e below. ​t-interval for mu ​: with 99 ​% ​confidence, 43623 less thanmu​(TchPay)less than45465 ​ a) If many random samples of 251 teachers from this state were​ taken, about 99 out of 100 of them would produce this...
According to a union agreement, the mean income for all senior-level assembly-line workers in a large...
According to a union agreement, the mean income for all senior-level assembly-line workers in a large company equals $490 per week. A representative of a women's group decides to analyze whether the mean income for female employees matches this norm. For a random sample of nine female employees, using software, she obtains a 95% confidence interval of (464 ,498 ). Explain what is wrong with each of the following interpretations of this interval. Complete parts a through d below.a. We...
The 2012 General Social Survey asked, “What do you think the ideal number of childrenfor a...
The 2012 General Social Survey asked, “What do you think the ideal number of childrenfor a family to have?” The 590 females who gave a numeric response from 0 to 6 had a median of 2,mean of ̄x= 2.56, and standard deviation ofs= 0.84. e) Based on the confidence interval (2.49, 2.62), is it plausible that the population meanμ= 2?Explain. f) Based on the confidence interval (2.49, 2.62), is it plausible that the population meanμ= 2.5?Explain. g) For males, the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT