Question

Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength...

Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength of these plastics is very important. From a random sample size of n1=18, and n2=16, we obtained that X1-bar=151.2, S1=1.4 and X2-bar=152.3, S2=1.65.

Calculate a 95% confidence interval on the ratio of variances.

With 95% confidence, what is the left-value of the two-sided confidence interval on the ratio of variances?

Your Answer:

Homework Answers

Answer #1




Lower Limit =
Upper Limit =
95% Confidence interval is ( 0.2562 , 1.9582 )
( 0.2562 <     < 1.9582 )

Left value = 0.2562

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength...
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength of these plastics is very important. From a random sample size of n1=18, and n2=16, we obtained that X1-bar=151.2, S1=1.4 and X2-bar=152.3, S2=1.65. Calculate a 95% confidence interval on the ratio of variances. With 95% confidence, what is the right-value of the two-sided confidence interval on the ratio of variances? Your Answer:
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength...
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength of these plastics is very important. From a random sample size of n1=18, and n2=16, we obtained that X1-bar=151.2, S1=1.4 and X2-bar=152.3, S2=1.65. Calculate a 95% confidence interval on the difference in means, assuming that the population variances are equal. With 95% confidence, what is the left-value of the two-sided confidence interval on the difference in means? Your Answer:
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength...
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength of these plastics is very important. From a random sample size of n1=18, and n2=16, we obtained that X1-bar=151.2, S1=1.4 and X2-bar=152.3, S2=1.65. Calculate a 90% confidence interval on the difference in means. With 90% confidence, what is the right-value of the two-sided confidence interval on the difference in means? Your Answer:
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength...
Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength of these plastics is very important. From a random sample size of n1=18, and n2=16, we obtained that X1-bar=151.2, S1=1.4 and X2-bar=152.3, S2=1.65. Calculate a 90% confidence interval on the difference in means. With 90% confidence, what is the left-value of the two-sided confidence interval on the difference in means? Your Answer:
two types of flares are tested for their burning times (in minutes) and sample results are...
two types of flares are tested for their burning times (in minutes) and sample results are given below. n1 = 35       n2 = 40 x1= 19.4     x2= 15.1 s1 = 1.4       s2= 0.8 assume we have unequal variance 1)Construct a 95% confidence interval for the differences μX - μY based on the sample data 2)Interpret the 95% confidence intervall
Consider the following data from two independent samples with equal population variances. Construct a 90% confidence...
Consider the following data from two independent samples with equal population variances. Construct a 90% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. x1 = 37.1 x2 = 32.2 s1 = 8.9 s2 = 9.1 n1 = 15 n2 = 16
Confidence Interval for 2-Means (2 Sample T-Interval) Given two independent random samples with the following results:...
Confidence Interval for 2-Means (2 Sample T-Interval) Given two independent random samples with the following results: n1=11 n2=17 x1¯=118 x2¯=155 s1=18 s2=13 Use this data to find the 99% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Round values to 2 decimal places. Lower and Upper endpoint?
Exercise 2. The following information is based on independent random samples taken from two normally distributed...
Exercise 2. The following information is based on independent random samples taken from two normally distributed populations having equal variances: Sample 1 Sample 2 n1= 15 n2= 13 x1= 50 x2= 53 s1= 5 s2= 6 Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means.
rovided below are summary statistics for independent simple random samples from two populations. Use the pooled​...
rovided below are summary statistics for independent simple random samples from two populations. Use the pooled​ t-test and the pooled​ t-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval. X1=20, S1=6, N1=21, X2=22, S2=7, N2= 15 Left tailed test, a=.05 90% confidence interval The 90% confidence interval is from ____ to ____
Two samples are taken with the following sample means, sizes, and standard deviations ¯x1 = 21...
Two samples are taken with the following sample means, sizes, and standard deviations ¯x1 = 21 ¯x2 = 29 n1 = 58 n2 = 56 s1 = 4 s2 = 3 Find a 87% confidence interval, round answers to the nearest hundredth. < μ1-μ2 <
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT