a coin has two sides: head and tails. a die has six
sides, numbered 1 through 6. if you flip the coin and roll the die,
what is the probability that you flip "heads" and roll an number
greater than 5
Here' the answer to the question. Please let me know in case you've doubts.
P(flip heads and roll a number on dice which is > 5) = ?
P(flip head in a coin toss) = 1/2, as out of 2 outcomes of heads and tails, 1 is a head
P(get > 5 on dice) = 1/6, because only 6 is >5, out of the 6 outcomes on a fair dice.
Rolling a dice and flipping a coin are 2 independent events, which means that if A and B are 2 independent events then P(A and B) = P(A)*P(B)
Using this concept we will say:
P(flip heads and roll a number on dice which is > 5)
= P(flip heads)*P(roll a dice with > 5)
= (1/2)*(1/6)
= 1/12
Answer: 1/12
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