8) (1 point) A professor using an open source introductory statistics book predicts that 10% of the students will purchase a hard copy of the book, 40% will print it out from the web, and 50% will read it online. At the end of the semester he asks his students to complete a survey where they indicate what format of the book they used. Of the 316 students, 14 said they bought a hard copy of the book, 137 said they printed it out from the web, and 165 said they read it online. Round all answers to four decimal places.
1. State the hypotheses for testing if the professor's predictions were inaccurate.
H0H0: The professor's predictions ? were were not accurate. The difference ? is is not due to chance.
HAHA: The professor's predictions ? were were not accurate. The difference ? is is not due to chance.
2. Enter the expected values for the hypothesis test in the table below:
Book Format | Expected Value |
Hard copy | |
Print from web | |
Read online |
3. Calculate the chi-squared statistic:
4. Calculate the degrees of freedom:
5. Calculate the p-value:
6. Based on the p-value, we have:
A. very strong evidence
B. some evidence
C. extremely strong evidence
D. strong evidence
E. little evidence
that the null model is not a good fit for our observed data.
applying chi square goodness of fit test: |
relative | observed | Expected | residual | Chi square | |
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
1 | 0.100 | 14.0 | 31.60 | -3.13 | 9.803 |
2 | 0.400 | 137.0 | 126.40 | 0.94 | 0.889 |
3 | 0.500 | 165.0 | 158.00 | 0.56 | 0.310 |
total | 1.000 | 316 | 316 | 11.0016 | |
test statistic X2 = | 11.0016 |
1)H0: The professor's predictions were accurate. The difference is due to chance.
Ha: The professor's predictions were not accurate. The difference is not due to chance.
2)
Book Format | Expected Value |
Hard copy | 31.6 |
Print from web | 126.4 |
Read online | 158 |
3)
chi-squared statistic=11.0016
4)
degree of freedom =categories-1= | 2 |
5)
p value =0.0041
6)]
A. very strong evidence
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