Question

4.4-JG1 Given the following joint density function in Example 4.4-1: fx,y(x,y)=(2/15)d(x-x1)d(y-y1)+(3/15)d(x-x2)d(y-y1)+(1/15)d(x-x2)d(y-y2)+(4/15)d(x-x1)d(y-y3) a) Determine fx(x|y=y1) Ans: 0.4d(x-x1)+0.6d(x-x2)...

4.4-JG1 Given the following joint density function in Example 4.4-1:
fx,y(x,y)=(2/15)d(x-x1)d(y-y1)+(3/15)d(x-x2)d(y-y1)+(1/15)d(x-x2)d(y-y2)+(4/15)d(x-x1)d(y-y3)
a) Determine fx(x|y=y1) Ans: 0.4d(x-x1)+0.6d(x-x2)
b) Determine fx(x|y=y2) Ans: 1d(x-x2)
c) Determine fy(y|x=x1) Ans: (1/3)d(y-y1)+(2/3)d(y-y3)
d) Determine fx(y|x=x2) Ans: (3/9)d(y-y1)+(1/9)d(y-y2)+(5/9)d(y-y3)

4.4-JG2
Given fx,y(x,y)=2(1-xy) for 0 a) fx(x|y=0.5) (Point Conditioning) Ans: (4/3)(1-x/2)
b) fx(x|0.5

Math   Statistics-And-Probability   
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