Question

Use the given confidence interval to find the margin of error and the sample proportion. ​(0.784​,0.808​)

Use the given confidence interval to find the margin of error and the sample proportion. ​(0.784​,0.808​)

Homework Answers

Answer #1

solution:

Given Confidence interval is ( 0.784 , 0.808 )

Let (a , b) =  ( 0.784 , 0.808 )

i) Margin of Error

The Margin of Error is half the width of Confidence interval

Margin of Error = (b - a ) / 2 = ( 0.808 - 0.784) / 2 = 0.024 / 2 =0.012

So, the Margin of Error = 0.012

ii) Sample proportion

The Sample proportion is the Centre of Confidence interval

   Sample proportion = ( a + b) / 2 = (0.784 + 0.808) / 2 = 1.592 / 2 = 0.796

So , the Sample proportion = 0.796  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use the given confidence interval to find the margin of error and the sample proportion. ​(0.767​,0.791​)
Use the given confidence interval to find the margin of error and the sample proportion. ​(0.767​,0.791​)
Use the given confidence interval to find the margin of error and the sample proportion. ​(0.6650.665​,0.6930.693​)...
Use the given confidence interval to find the margin of error and the sample proportion. ​(0.6650.665​,0.6930.693​) E =
Use the given confidence interval to find the margin of error and the sample proportion. ​(0.764​,0.788​)...
Use the given confidence interval to find the margin of error and the sample proportion. ​(0.764​,0.788​) Eequals nothing ​(Type an integer or a​ decimal.) ModifyingAbove p with caretequals nothing ​(Type an integer or a​ decimal.)
1) Use the given confidence interval to find the margin of error and the sample mean....
1) Use the given confidence interval to find the margin of error and the sample mean. ​(12.8​,19.8​) 2) In a random sample of four microwave​ ovens, the mean repair cost was ​$60.00 and the standard deviation was ​$12.00. Assume the population is normally distributed and use a​ t-distribution to construct a 99​% confidence interval for the population mean ?. What is the margin of error of ? Interpret the results.
Use the given confidence interval to find the margin of error and the sample mean. ​(72.5​,86.1​)
Use the given confidence interval to find the margin of error and the sample mean. ​(72.5​,86.1​)
Find the margin of error for the 95% confidence interval used to estimate the population proportion....
Find the margin of error for the 95% confidence interval used to estimate the population proportion. 12) In clinical test with 2349 subjects. 1232 showed improvement from the treatment Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p 13) n=101,x=73;88 percent
find point estimate of population proportion margin error confidence interval number in sample
find point estimate of population proportion margin error confidence interval number in sample
Use the normal distribution to find a confidence interval for a proportion p given the relevant...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for the proportion who will answer ‘‘Yes” to a question, given that 60 answered yes in a random sample of 95 people. Round your answers to three decimal places. Point estimate = Margin of error...
Use the Confidence Interval to find the Margin of Error and the Sample mean: 1) (45.67,...
Use the Confidence Interval to find the Margin of Error and the Sample mean: 1) (45.67, 57.82) Margin of Error =  , Sample mean = 2) (12.05,12.23) Margin of Error =  , Sample mean = Do not round your answers.
#10. Use the confidence interval to find the margin of error and the sample mean. (0.170,1.96)
#10. Use the confidence interval to find the margin of error and the sample mean. (0.170,1.96)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT