Find the critical values, z-scores, for the following confidence intervals by showing a graph and respective areas: (Please show all work)
a.) 90% z-scores b.) 99% t-scores, n=51
Solution :
Given that,
a ) At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
The critical value = 1.645
b ) n = 51
Degrees of freedom = df = n - 1 = 51 - 1 = 50
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t /2,df = t0.005,50 = 2.679
The critical value = 2.679
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