The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of five per hour. By using Poisson Distributions. Find:
(i) What is the probability that exactly four arrivals occur during a particular hour?
(ii) What is the probability that at least four people arrive during a particular hour?
(iii) What is the probability that at least one person arrive during a particular minute?
(iv) How many people do you expect to arrive during a 50- min period?
i)
this is Poisson distribution with parameter λ=5 |
probability that exactly four arrivals occur during a particular hour:
P(X=4)= | {e-5*54/4!} = | 0.1755 |
(Note:
if using ti-84 use commannd :poissonpdf(5,4) |
if using excel use commannd :poisson(4,5,false) |
)
ii)
probability that at least four people arrive during a particular hour:
P(X>=4)=1-P(X<=3)= | 1-∑x=0x e-λ*λx/x! = | 0.7350 |
(Note:
if using ti-84 use command :1-poissoncdf(5,3) |
if using excel use commannd :1-poisson(3,5,true) |
)
iii) expected number in 1 minute =5/60=1/12
probability that at least one person arrive during a particular minute:
P(X>=1) =1-P(X=0) =1-e-1/12 =0.0800
iv)
expected number of arrivals in 50 min period =50*5/60= 4.167
Get Answers For Free
Most questions answered within 1 hours.