Question

For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.

In a survey of 1000 large corporations, 246 said that, given a choice between a job candidate who smokes and an equally qualified nonsmoker, the nonsmoker would get the job.

(a) Let p represent the proportion of all corporations preferring a nonsmoking candidate. Find a point estimate for p. (Round your answer to four decimal places.)


(b) Find a 0.95 confidence interval for p. (Round your answers to three decimal places.)

A random sample of 328 medical doctors showed that 166 had a solo practice.

(a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.)


(b) Find a 95% confidence interval for p. (Use 3 decimal places.)

lower limit
upper limit

Give a brief explanation of the meaning of the interval.

95% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.95% of the all confidence intervals would include the true proportion of physicians with solo practices.     5% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.5% of the all confidence intervals would include the true proportion of physicians with solo practices.

(c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice?

Report p̂ along with the margin of error.Report p̂.     Report the margin of error.Report the confidence interval.

What is the margin of error based on a 95% confidence interval? (Use 3 decimal places.)

A random sample of 328 medical doctors showed that 166 had a solo practice.

(a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.)


(b) Find a 95% confidence interval for p. (Use 3 decimal places.)

lower limit
upper limit

Give a brief explanation of the meaning of the interval.

95% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.95% of the all confidence intervals would include the true proportion of physicians with solo practices.     5% of the confidence intervals created using this method would include the true proportion of physicians with solo practices.5% of the all confidence intervals would include the true proportion of physicians with solo practices.

(c) As a news writer, how would you report the survey results regarding the percentage of medical doctors in solo practice?

Report p̂ along with the margin of error.Report p̂.     Report the margin of error.Report the confidence interval.

What is the margin of error based on a 95% confidence interval? (Use 3 decimal places.)

(c) As a news writer, how would you report the survey results regarding the proportion of corporations that would hire the equally qualified nonsmoker?

Report p̂ along with the margin of error.Report p̂.     Report the margin of error.

What is the margin of error based on a 95% confidence interval? (Round your answer to three decimal places.)

Answer 1

My dear student I am allowed to solve one question at a time so I am solving the first question in the pic. Thank you