Question

Given the sample mean, x, the assumed population mean, μ, the sample standard deviation,s, and the...

  1. Given the sample mean, x, the assumed population mean, μ, the sample standard deviation,s, and the sample size, n, what is the formula to compute the t-statistic for our sample mean? In other words, what is the t-score in “the x distribution”? What is the number of degrees of freedom?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Given the population mean, μ = 45, and the population standard deviation, σ = 15 with...
Given the population mean, μ = 45, and the population standard deviation, σ = 15 with a sample size of, n = 100.n = 100. Determine P ( x ¯ ≤ 42 ). To do this problem first determine the sampling mean and the sampling standard deviation in order to convert to a z-score. Round your answer to 4 decimals.
1. For a population with a mean of μ = 55 and a standard deviation of...
1. For a population with a mean of μ = 55 and a standard deviation of σ = 24, what is the standard error of the distribution of sample means for a sample size of n=22? 2. If the population standard deviation is S= 17, how large a sample is necessary to have a standard error that is less than 10 points?
Given a normal distribution with population standard deviation of 2 and a mean of μ =...
Given a normal distribution with population standard deviation of 2 and a mean of μ = 10. If a random sample of size 69 is drawn, find P(10 ≤ x ≤ 12). Round to three decimal places.
A population has a mean μ=40 and a standard deviation σ=4. What is the standard deviation...
A population has a mean μ=40 and a standard deviation σ=4. What is the standard deviation of the sampling distribution of the sample means if the sample size is n=16?
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 45 business​ days, the mean closing price of a certain stock was ​$116.70. Assume the population standard deviation is ​$11.02. The​ 90% confidence interval is ​( ​, ​). Construct the indicated confidence interval for the population mean μ...
The population has mean μ=29 and standard deviation σ=9. This distribution is shown with the black...
The population has mean μ=29 and standard deviation σ=9. This distribution is shown with the black dotted line. We are asked for the mean and standard deviation of the sampling distribution for a sample of size 34. The Central Limit Theorem states that the sample mean of a sample of size n is normally distributed with mean μx¯=μ and σx¯=σn√. In our case, we have μ=29, σ=9, and n=34. So, μx¯=29 and σx¯=934‾‾‾√=1.5 This distribution is shown with the red...
a.) Given a normal distribution with population standard deviation of 21 and a mean of μ...
a.) Given a normal distribution with population standard deviation of 21 and a mean of μ = 29. If a random sample of size 62 is drawn, find P(29 ≤ x ≤ 31). Round to three decimal places. b.) Find the positive z value such that 89% of the standard normal curve lies between –z and z. (Use 2 decimal places.) c.) For a standard normal curve, find the area between z = 0.28 and z = 1.95. (Use 4...
From a population that is not normally distributed and whose standard deviation is not known, a...
From a population that is not normally distributed and whose standard deviation is not known, a sample of 6 items is selected to develop an interval estimate for the mean of the population (μ). Multiple Choice b. The normal distribution can be used. a. The t distribution with 6 degrees of freedom must be used. d. The sample size must be increased. c. The t distribution with 5 degrees of freedom must be used. THE ANSWER IS NOT C) T...
A population has a mean μ=78 and a standard deviation σ=22. Find the mean and standard...
A population has a mean μ=78 and a standard deviation σ=22. Find the mean and standard deviation of a sampling distribution of sample means with sample size n=264. μx= ?????
A random sample is selected from a population with mean μ = 102 and standard deviation...
A random sample is selected from a population with mean μ = 102 and standard deviation σ = 10. Determine the mean and standard deviation of the x sampling distribution for each of the following sample sizes. (Round the answers to three decimal places.) (a) n = 12 μ =   σ =   (b) n = 13 μ =   σ =   (c) n = 37 μ =   σ =   (d) n = 70 μ =   σ =   (f) n = 140...