The mean lifetime of a tire is 48 months with a standard deviation of 7 months. If 147 tires are sampled, what is the probability that the mean of the sample would be greater than 48.83 months? Round your answer to four decimal places.
Solution :
Given that ,
mean = = 48
standard deviation = = 7
n = 147
= 48
= / n = 7/ 147 = 0.5774
P( >48.83 ) = 1 - P( <48.83 )
= 1 - P[( - ) / < (48.83 -48) /0.5774 ]
= 1 - P(z <1.44 )
Using z table
= 1 - 0.9251
= 0.0749
probability= 0.0749
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