Consider the following time series data:
Month | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Value | 23 | 13 | 21 | 13 | 19 | 21 | 17 |
(a) | Create a time series plot. |
What type of pattern exists in the data? | |
- Select your answer -Positive trend patternHorizontal patternVertical patternNegative trend patternItem 2 | |
(b) | Develop a three-month moving average for this time series. Compute MSE and a forecast for month 8. |
If required, round your answers to two decimal places. Do not round intermediate calculation. | |
MSE: | |
The forecast for month 8: | |
(c) | Use α = 0.2 to compute the exponential smoothing values for the time series. Compute MSE and a forecast for month 8. |
If required, round your answers to two decimal places. Do not round intermediate calculation. | |
MSE: | |
The forecast for month 8: | |
(d) | Compare the three-month moving average forecast with the exponential smoothing forecast using α = 0.2. Which appears to provide the better forecast based on MSE? |
- Select your answer -3-month moving averageexponential smoothingItem 7 | |
(e) | Use trial and error to find a value of the exponential smoothing coefficient α that results in the smallest MSE. |
If required, round your answer to two decimal places. |
a)
Horizontal
b)
month | value | forecast | error | error^2 |
1 | 23 | |||
2 | 13 | |||
3 | 21 | |||
4 | 13 | 19.00 | -6.00 | 36.00 |
5 | 19 | 15.67 | 3.33 | 11.11 |
6 | 21 | 17.67 | 3.33 | 11.11 |
7 | 17 | 17.67 | -0.67 | 0.44 |
total | 58.67 |
MSE=14.67
forecast =19
c)
month | value | forecast | error | error^2 |
1 | 23 | |||
2 | 13 | 23.00 | -10.00 | 100.00 |
3 | 21 | 21.00 | 0.00 | 0.00 |
4 | 13 | 21.00 | -8.00 | 64.00 |
5 | 19 | 19.40 | -0.40 | 0.16 |
6 | 21 | 19.32 | 1.68 | 2.82 |
7 | 17 | 19.66 | -2.66 | 7.05 |
total | 174.04 |
MSE=29.01
forecast =19.13 (try 19.12 if this comes wrong)
d) three-month moving average forecast o provide the better forecast due to smaller MSE
e)
alpha =0.32
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