There are 18 students in a group,15 of them passed math exam. 7 students from this group are chosen at random. Find a probability that less than 3 of them did not pass math exam.
Probability of number of students passed in a math exam is 15/18
That is p=15/18
In this case number of students choose at random is 7
that is n=7
here we want to calculate the probability that less than 3 of them did not pass the math exam
That is P(X<3)
Here X ~Binomial(n=7,p=.833)
so P(X<3)= P(X=2)+P(X=1)+P(X=0)
By solving this we get the answer as
=.0015776
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