14) One truck from Lakeland Trucking, Inc. can carry a load of 3880.8 lb. Records show that the weights of loads have a mean of 3500 lb and a standard deviation of 140 lb. For samples of size 49, find the mean and standard deviation of .
Solution :
Given that ,
mean = = 3500
standard deviation = = 140
n = 49
sample distribution of sample mean is ,
=
= 3500
sampling distribution of standard deviation
= / n = 140/ 49
= 20
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