Question

Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch hour. To evaluate the program, he selected a random sample of eight participants and found the number of days each was absent in the six months before the exercise program began and in the six months following the exercise program. Below are the results.

Employee	Before	After
1	7	3
2	7	6
3	5	3
4	6	7
5	4	4
6	5	4
7	6	3
8	5	2

At the 0.050 significance level, can he conclude that the number of absences has declined? Estimate the p-value.

1. State the decision rule for 0.050 significance level. (Round your answer to 3 decimal places.)

2. Compute the test statistic. (Round your answer to 3 decimal places.)

3. The p-value is

• Between 0.01 And 0.025

• Between 0.001 And 0.005

• Between 0.005 And 0.01

4. State your decision about the null hypothesis.

• Reject H₀

• Fail to reject H₀

_{Please help (:}

Answer 1

a)

for 0.05 level with right tailed test and n-1= 7 df, critical value of t=				1.895
Decision rule: reject Ho if test statistic t>1.895

b)

test statsitic t =2.728

c)Between 0.01 And 0.025
d)

Reject H₀