Question

At a certain college, 50% of all students take advantage of free tutoring services. A sample...

At a certain college, 50% of all students take advantage of free tutoring services. A sample of 36 students is selected. what is the probability that the proportion of students who take advantage of free tutoring services in the sample between .485 and .580? Show the functions using the TI-84 calculator

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1
for normal distribution z score =(p̂-p)/σp
here population proportion=     p= 0.500
sample size       =n= 36
std error of proportion=σp=√(p*(1-p)/n)= 0.0833
probability =P(0.485<X<0.58)=P((0.485-0.5)/0.083)<Z<(0.58-0.5)/0.083)=P(-0.18<Z<0.96)=0.8315-0.4286=0.4029

NOte:

if using ti-84 press 2nd - vars -use command :normalcdf(0.485,0.58,0.5,0.0833)
0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
At a certain college 50% of all students take advantage of free tutoring services a sample...
At a certain college 50% of all students take advantage of free tutoring services a sample of 36 students is selected. What is the probability that the proportion of students who take advantage of free tutoring services in the sample is between 0.482 and 0.580
t a certain college, 50% of all students take advantage of free tutoring services. A sample...
t a certain college, 50% of all students take advantage of free tutoring services. A sample of 36 students is selected. What is the probability that the proportion of students who take advantage of free tutoring services in the sample is between 0.484 and 0.580? Round to four decimal places.
At a certain college, 50% of all students take advantage of free tutoring services. A sample...
At a certain college, 50% of all students take advantage of free tutoring services. A sample of 36 students is selected. What is the probability that the proportion of students who take advantage of free tutoring services in the sample is between 0.477 and 0.580? Write only a number as your answer. Round to 4 decimal places (for example 0.3748). Do not write as a percentage.
At a certain college, 50% of all students take advantage of free tutoring services. A sample...
At a certain college, 50% of all students take advantage of free tutoring services. A sample of 36 students is selected. What is the probability that the proportion of students who take advantage of free tutoring services in the sample is between 0.489 and 0.580? Write only a number as your answer. Round to 4 decimal places (for example 0.3748). Do not write as a percentage.
At a certain college, 50% of all students take advantages of free tutoring services. A sample...
At a certain college, 50% of all students take advantages of free tutoring services. A sample of 36 Students is selected. What is the probability that the proportion of students who take advantage of free tutoring services in the sample is between 0.482 and 0.580? Write only a number as your answer. Round to 4 decimal places (for example 0.3748). Do not write a percentage.
77% of all students at a college still need to take another math class. If 48...
77% of all students at a college still need to take another math class. If 48 students are randomly selected, find the probability that a. Exactly 35 of them need to take another math class. b. At most 38 of them need to take another math class. c. At least 37 of them need to take another math class. d. Between 32 and 36 (including 32 and 36) of them need to take another math class.
at a certain university, 50% of all entering freshmen planned to major in a STEM discipline....
at a certain university, 50% of all entering freshmen planned to major in a STEM discipline. a sample of 36 freshmen is selected. what is the probability that the proportion of freshmen in the sample is between 0.484 and 0.580? Round to four decimal places
78% of all students at a college still need to take another math class. If 36...
78% of all students at a college still need to take another math class. If 36 students are randomly selected, find the probability that a. Exactly 27 of them need to take another math class. b. At most 27 of them need to take another math class. c. At least 27 of them need to take another math class. d. Between 23 and 30 (including 23 and 30) of them need to take another math class.
A student was asked to find a 90% confidence interval for the proportion of students who...
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sample of size n = 84. Which of the following is a correct interpretation of the interval 0.1 < p < 0.31? Check all that are correct. With 90% confidence, a randomly selected student takes notes in a proportion of their classes that is between 0.1 and 0.31. There is a 90% chance that the proportion of...
A student was asked to find a 98% confidence interval for the population proportion of students...
A student was asked to find a 98% confidence interval for the population proportion of students who take notes using data from a random sample of size n = 84. Which of the following is a correct interpretation of the interval 0.1 < p < 0.33? Check all that are correct. ____With 98% confidence, the proportion of all students who take notes is between 0.1 and 0.33. ____The proprtion of all students who take notes is between 0.1 and 0.33,...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT