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At a certain college, 50% of all students take advantage of free tutoring services. A sample...

At a certain college, 50% of all students take advantage of free tutoring services. A sample of 36 students is selected. what is the probability that the proportion of students who take advantage of free tutoring services in the sample between .485 and .580? Show the functions using the TI-84 calculator

Math   Statistics-And-Probability   
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Answer #1
for normal distribution z score =(p̂-p)/σp
here population proportion=     p= 0.500
sample size       =n= 36
std error of proportion=σp=√(p*(1-p)/n)= 0.0833
probability =P(0.485<X<0.58)=P((0.485-0.5)/0.083)<Z<(0.58-0.5)/0.083)=P(-0.18<Z<0.96)=0.8315-0.4286=0.4029

NOte:

if using ti-84 press 2nd - vars -use command :normalcdf(0.485,0.58,0.5,0.0833)
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