Question

A random sample of size n=632n=632 from a population whose parameter is p=0.24p=0.24.

1. What is the mean of the distribution of sample means? Round the answer accurate to 2 decimal places.
   
   
2. What is the standard deviation of the distribution of sample means? Round the answer accurate to 2 decimal places.
   

Answer 1

Solution

Given that,

p = 0.24

1 - p = 1-0.24=0.76

n = 632

mean of the distribution of sample means

= p =0.24

standard deviation of the distribution of sample means=

=  [p ( 1 - p ) / n] =   [(0.24*0.76) / 632 ] = 0.02