Question

In a recent poll, 390 people were asked if they liked dogs,
and 76% said they did. Find the Margin of Error for this poll, at
the 95% confidence level. Give your answer to four decimal places
if possible.

Answer #1

Solution :

The margin of error to estimate the population proportion with 95% confidence level is given as follows :

Where, Z_{(0.05/2)} is critical z-value (two-tailed) at
95% confidence level, p̂ is sample proportion and n is sample
size.

Sample proportion of people who liked dogs is, p̂ = 76% = 0.76

n = 390

Using Z-table we get, Z_{(0.05/2)} = 1.96

Hence, the margin of error at 95% confidence level is,

**Hence, the margin of error for the poll is
0.0424**.

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[________, ________]

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--Use z = 1.645 for a 90% confidence interval
--Use z = 2 for a 95% confidence interval
--Use z = 2.576 for a 99% confidence interval.
Give your answers as decimals, to 4 decimal places.
[,]

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Give your answer to three decimals
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______<...

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