Solution :
The margin of error to estimate the population proportion with 95% confidence level is given as follows :
Where, Z(0.05/2) is critical z-value (two-tailed) at 95% confidence level, p̂ is sample proportion and n is sample size.
Sample proportion of people who liked dogs is, p̂ = 76% = 0.76
n = 390
Using Z-table we get, Z(0.05/2) = 1.96
Hence, the margin of error at 95% confidence level is,
Hence, the margin of error for the poll is 0.0424.
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