The scores of individual students on the American College Testing (ACT) program composite college entrance examination have a normal distribution with mean 18.6 and standard deviation 6.0. Forty-nine randomly selected seniors take the ACT test. What is the probability that their mean score is less than 18? Round your answer to 4 decimal places.
Solution :
Given that ,
mean = = 18.6
standard deviation = = 6
n = 49
= 18.6
= / n = 6 / 49=0.857
P( < 18) = P[( - ) / < (18-18.6) /0.857 ]
= P(z < -0.70)
Using z table
= 0.2420
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