Question

In a particular community of 10,000 individuals, 40% are male,
15% are hypertensive and 80% of females are non-hypertensive. Note
that you do not need to use probability for any part of this
problem!

5. How many individuals were females?

6. How many individuals were hypertensive? 1

7. How many female individuals were hypertensive?

8. How many male individuals were non-hypertensive?

Answer #1

Total number of individuals = 10000

40% are males and remaining 60% are females.

Number of males = 10000 * 0.40 = 4000

Number of females = 10000 * 0.60 = 6000

15% are hypertensive and remaining 85% are non-hypertensive.

Number of hypertensive = 10000 * 0.15 = 1500

Number of non-hypertensive = 10000 * 0.85 = 8500

80% of females are non-hypertensive.

Number of females are non-hypertensive = 6000 * 0.80 = 4800.

Using above information we get following table,

Hypertensive | Non-Hypertensive | Total | |
---|---|---|---|

Male | 300 | 3700 | 4000 |

Female | 1200 | 4800 | 6000 |

Total | 1500 | 8500 | 10000 |

Therefore, we get,

5) **6000** individuals were females.

6) **1500** individuals were hypertensive.

7) **1200** female individuals were
hypertensive.

8) **3700** male individuals were
non-hypertensive.

Case
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Male
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3
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