Question

# In a particular community of 10,000 individuals, 40% are male, 15% are hypertensive and 80% of...

In a particular community of 10,000 individuals, 40% are male, 15% are hypertensive and 80% of females are non-hypertensive. Note that you do not need to use probability for any part of this problem!
5. How many individuals were females?
6. How many individuals were hypertensive? 1
7. How many female individuals were hypertensive?
8. How many male individuals were non-hypertensive?

Total number of individuals = 10000

40% are males and remaining 60% are females.

Number of males = 10000 * 0.40 = 4000

Number of females = 10000 * 0.60 = 6000

15% are hypertensive and remaining 85% are non-hypertensive.

Number of hypertensive = 10000 * 0.15 = 1500

Number of non-hypertensive = 10000 * 0.85 = 8500

80% of females are non-hypertensive.

Number of females are non-hypertensive = 6000 * 0.80 = 4800.

Using above information we get following table,

Hypertensive Non-Hypertensive Total
Male 300 3700 4000
Female 1200 4800 6000
Total 1500 8500 10000

Therefore, we get,

5) 6000 individuals were females.

6) 1500 individuals were hypertensive.

7) 1200 female individuals were hypertensive.

8) 3700 male individuals were non-hypertensive.