Find the minimum sample size n needed to estimate mu for the given values of c, sigma, and E. cequals0.95, sigmaequals7.7, and Eequals2 Assume that a preliminary sample has at least 30 members.
Solution
standard deviation = =7.7
Margin of error = E =2
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table ( see the 0.025 value in standard normal (z) table corresponding z value is 1.96 )
sample size = n = [Z/2* / E] 2
n = ( 1.96* 7.7 /2 )2
n =56.9
Sample size = n =57
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