A)
N = 1896
P = 0.48
standard error = √{p*(1-p)}/√n = 0.01147369032
B)
First we need to check the conditions of normality that is if n*p and n*(1-p) both are greater than 5 or not
N*p = 910
N*(1-p) = 976
Both the conditions are met so we can use standard normal z table to estimate the interval
Critical value z from z table for 95% confidence level is 1.96
Margin of error (MOE) = Z*STANDARD ERROR = 0.02248843303
Confidence interval is given by
P + or - MOE
0.48 + or - 0.02248843303
C)
(P-MOE, P+MOE)
(45.75%, 50.25%)
D)
We are 95% confident that true population proportion lies in between 0.4575 and 0.5025
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