A group of researchers developed a 95% z confidence interval for the mean body mass index (BMI) of women aged 20 to 29 years, based on a national random sample of 647 such women. They assumed that the population standard deviation was known to be σ = 7.5. In fact, the sample data had mean BMI x = 26.9 and standard deviation s = 7.39. What is the 95% tconfidence interval for the mean BMI of all young women? (Round your answers to three decimal places.)
Answer: ___ to ____
Solution :
Given that,
Point estimate = sample mean =
= 26.9
Population standard deviation =
= 7.5
Sample size = n = 647
At 95% confidence level
= 1 - 95%
= 1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.96
Margin of error = E = Z/2
* (
/n)
= 1.96 * ( 7.5 / 647
)
= 0.578
At 95% confidence interval estimate of the population mean is,
± E
26.9 ± 0.578
( 26.322 to 27.478 )
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