From the data,
sample mean = 0.1569
sample standard deviation s = 0.08347381
standard error of mean = s/ = 0.08347381 / = 0.02639674
Degree of freedom = n-1 = 10-1 = 9
Critical value of t at df = 9 and 95% confidence level is 2.26
95% confidence interval of the mean concentration of calcium precipitation is,
(0.1569 - 2.26 * 0.02639674 , 0.1569 + 2.26 * 0.02639674)
(0.097 , 0.217)
Since the 95% confidence interval contains the value of 0.15 milligrams per liter of 1990 level, we can conclude that the calcium concentrations have significantly not changed since 1990.
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