1. Here given is
n = 200, p = 0.60
expect number of people to watch TV via a streaming service = np = 200 * 0.60 = 120
2. For central limit condition to follow,
np > 5 and nq > 5
here both conditions are fulfilled so central limit theorm will follow.
3. standard error = sqrt [p*(1-p) *n] = sqrt [0.60 * 0.40 * 200] = 6.93
4. Here
P(n > 125)
Z = (125 - 120)/6.93= 0.722
P(n > 125) = 1 - P(Z < 0.722) = 1 - 0.7648 = 0.2352
no we would not be surprise that more than 125 people in the sample stream their TV shows as the probability of that event is not unusual or rare to happen.
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