The data collected here is of 6 different birds,13 sparrows, 10 finches, 7 cardinals, 5 robins, 5 chickadees, and 4 bluejays. So, there are six groups here, of unequal sample sizes. We want to test if one species visits the feeder more than the others, i.e , we have to test the equality of means for six groups. Hence, a t test would not be valid as there are more than two groups. We use ANOVA for testing the equality of means of more than two groups. Hence, the correct answer is ANOVA.
Get Answers For Free
Most questions answered within 1 hours.