Suppose 52% of the population has a college degree. If a random sample of size 563 is selected, what is the probability that the proportion of persons with a college degree will differ from the population proportion by more than 5%? Round your answer to four decimal places.
|for normal distribution z score =(p̂-p)/σp|
|here population proportion= p=||0.520|
|sample size =n=||563|
|std error of proportion=σp=√(p*(1-p)/n)=||0.0211|
proportion of persons with a college degree will differ from the population proportion by more than 5%
=0.0176 (please try 0.0178 if this comes wrong due to rounding error and revert)
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