Question

A random sample found that forty-two percent of 100 Americans were satisfied with the gun control laws in 2017. Compute a 90% confidence interval for the true proportion of Americans who were satisifed with the gun control laws in 2017. Fill in the blanks appropriately. A 90% for the true proportion of Americans who were satisifed with the gun control laws in 2017 is (?, ? ) (Keep 3 decimal places)

Answer 1

We have given,              
              
x=42          
n=100          
Estimate for sample proportion
Level of significance is =1-0.90=0.1      
Z critical value(using Z table)=1.645  
  
Confidence interval formula is              


=(0.339,0.501)