You are testing the following hypothesis: H0: m = 72 HA: m ≠ 72 Your sample size if n = 36 and your sample standard deviation is equal to 12. If your sample mean is equal to 69.2, the appropriate conclusion would be to reject the null hypothesis at a significance level of... Select one:
Select one:
a. 0.10
b. 0.05
c. 0.02
d. 0.01
e. None of the above.
Solution,
The null and alternative hypothesis is ,
H0 : = 72
Ha : 72
= 69.2
s = 12
n = 36
Test statistic = t =
= ( - ) / s / n
= (69.2 - 72) / 12 / 36
Test statistic = t = -1.40
degrees of freedom = n - 1 = 36 - 1 = 35
P( t < -1.40)
= 0.0852
This is the two tailed test
P-value = 2 * P( t < -1.40)
P-value = 2 * 0.0852
P-value = 0.1704
all significance level less than P-value.
correct option is = e
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