5) If it is appropriate to do so, use the normal approximation to the p^-distribution to calculate the indicated probability:
n=60,p=0.40n=60,p=0.40
P( p̂ < 0.50)= ?
Enter 0 if it is not appropriate to do so.
Solution
Given that,
p = 0.40
1 - p = 1 -0.40 =0.60
n = 60
= p =0.40
= [p ( 1 - p ) / n] = [(0.40*0.60) / 60 ] = 0.063245553
P( <0.50 ) =
= P[( - ) / < (0.50 -0.40) /0.063245553 ]
= P(z < 1.58)
Using z table,
=0.9429
probability=0.9429
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