Question

5) If it is appropriate to do so, use the normal approximation to the  p^-distribution to calculate the indicated probability:

n=60,p=0.40n=60,p=0.40

P( p̂  < 0.50)= ?

Enter 0 if it is not appropriate to do so.

Answer 1

Solution

Given that,

p = 0.40

1 - p = 1 -0.40 =0.60

n = 60

= p =0.40

=  [p ( 1 - p ) / n] =   [(0.40*0.60) / 60 ] = 0.063245553

P( <0.50 ) =

= P[( - ) / < (0.50 -0.40) /0.063245553 ]

= P(z < 1.58)

Using z table,   

=0.9429

probability=0.9429