Question

**5)** If it is appropriate to do so, use the
normal approximation to the p^-distribution to calculate
the indicated probability:

n=60,p=0.40n=60,p=0.40

P( p̂ < 0.50)= ?

Enter 0 if it is not appropriate to do so.

Answer #1

Solution

Given that,

p = 0.40

1 - p = 1 -0.40 =0.60

n = 60

= p =0.40

= [p ( 1 - p ) / n] = [(0.40*0.60) / 60 ] = 0.063245553

P( <0.50 ) =

= P[( - ) / < (0.50 -0.40) /0.063245553 ]

= P(z < 1.58)

Using z table,

=0.9429

probability=0.9429

If it is appropriate to do so, use the normal approximation to
the p^ p^ -distribution to calculate the
indicated probability:
Standard Normal Distribution Table
n=80,p=0.715n=80,p=0.715
P( p̂ > 0.75)P( p̂ > 0.75) =
Enter 0 if it is not appropriate to do so.
Please provide correct answer. thanks

If it is appropriate to do so, use the normal approximation to
the p^ p^ -distribution to calculate the
indicated probability:
n=80,p=0.715
P(p>0.75)=?

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Standard Normal Distribution Table
n=80,p=0.715n=80,p=0.715
P( p̂ > 0.75)P( p̂ > 0.75) =
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