Question

Physicians at a college campus health clinic are concerned about the rising rates of chlamydia among...

Physicians at a college campus health clinic are concerned about the rising rates of chlamydia among the student body. Assume national statistics state that the prevalence of chlamydia among university aged students is 11%. The physicians at the college health clinic sampled 134 students and found that 29 of them were confirmed positive for chlamydia.

A) Conduct a formal test to determine if the prevalence of chlamydia is statistically different from the national statistics at the alpha level of 0.05. Write out your null and alternative hypotheses and interpret your results.

B) Construct a 95% confidence interval about your estimate for the prevalence of chlamydia at the college campus.

PLEASE CHOOSE THE MOST APPROPRIATE OPTION ( Please do not post calculations that do not match the options given, I must choose one of the options and I cannot get to the right answer, thank you.

Option 1

A) Ho: p=0.11, Ha: p≠0.11

Z statistic=39.364

Pvalue=<0.0001

Accept the null hypothesis, and conclude that the proportion of chlamydia cases on the college campus is in fact the same as the national average for the age demographic.

B) Ci (1.055, 2.094)

Option 2

A) Ho: p=0.11, Ha: p≠0.11

Z statistic=12.364

Pvalue=<0.01

Reject the null hypothesis, and conclude that the proportion of chlamydia cases on the college campus is in fact greater than the national average for the age demographic.

B) Ci (.0025, 0.0074)


Option 3

A) Ho: p=0.11, Ha: p≠0.11

Z statistic=3.9364

Pvalue=<0.0001

Reject the null hypothesis, and conclude that the proportion of chlamydia cases on the college campus is in fact greater than the national average for the age demographic.

B) Ci (0.155, 0.294)

Homework Answers

Answer #1

Correct option is 3

A) Ho: p=0.11, Ha: p≠0.11

Z statistic=3.9364

Pvalue=<0.0001

Reject the null hypothesis, and conclude that the proportion of chlamydia cases on the college campus is in fact greater than the national average for the age demographic.

B) Ci (0.155, 0.294)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Write out the null and alternative hypotheses for the following hypothetical proposal. Carry out a one-sample...
Write out the null and alternative hypotheses for the following hypothetical proposal. Carry out a one-sample Z test to determine significance at the α=0.05 level. PROPOSAL Recent scientific literature has suggested a link between exposure to the endocrine disruptor Bisphenol A (BPA) found ubiquitously in many plastic materials, and precocious puberty in adolescents. The transmission is maternal to child during the last weeks of gestation. Scientists can trace the presence of BPA in children for years after birth, and believe...
6.16 Is college worth it? Part I: Among a simple random sample of 331 American adults...
6.16 Is college worth it? Part I: Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school. (a) A newspaper article states that only a minority of the Americans who decide not to go to college do so because they cannot afford it and uses the point estimate from this survey...
A researcher is concerned that his new antihypertensive medication may be causing insomnia in some of...
A researcher is concerned that his new antihypertensive medication may be causing insomnia in some of his patients. Suppose he gathers a SRS of 65 patients treated with the study drug with a sample average of 6.6 hours of sleep and a σ=1.1. Assuming that insomnia can be quantified as an average of 4.5 hours of sleep, can we determine with 95% confidence that his drug avoids diagnosis of insomnia as a side-effect?                Ho: µ=4.5, Ha: µ<4.5 Z stat=12.4...
Are most student government leaders extroverts? According to Myers-Briggs estimates, about 82% of college student government...
Are most student government leaders extroverts? According to Myers-Briggs estimates, about 82% of college student government leaders are extroverts.† Suppose that a Myers-Briggs personality preference test was given to a random sample of 70 student government leaders attending a large national leadership conference and that 57 were found to be extroverts. Does this indicate that the population proportion of extroverts among college student government leaders is different (either way) from 82%? Use α = 0.01. (a) What is the level...
Cars on Campus. Statistics students at a community college wonder whether the cars belonging to students...
Cars on Campus. Statistics students at a community college wonder whether the cars belonging to students are, on average, older than the cars belonging to faculty. They select a random sample of 49 cars in the student parking lot and find the average age to be 9.7 years with a standard deviation of 6.7 years. A random sample of 49 cars in the faculty parking lot have an average age of 3.1 years with a standard deviation of 3.2 years....
Question 21 Suppose a health insurance company is interested in carrying out an investigation as to...
Question 21 Suppose a health insurance company is interested in carrying out an investigation as to the annual expenditures per household on their healthcare costs. In order to most accurately report their figures, the company decides to ensure “virtual certainty” about their estimates by using a Z value of 3.0 for their calculations. The company conducts a SRS of 843 households and determines the sample average household expenditures on healthcare is $43,257.00. A) Assume the company uses a σ=$879.00. Calculate...
During one particular war, the U.S. military was concerned about the nutrition of its recruits. Many...
During one particular war, the U.S. military was concerned about the nutrition of its recruits. Many did not have a sufficient number of teeth to chew the food provided to soldiers. As a result, it was likely that they would be undernourished and unable to fulfill their duties as soldiers. The requirements at that time specified that a recruit must have "at least four sound double teeth, one above and one below on each side of the mouth, and so...
During one particular war, the U.S. military was concerned about the nutrition of its recruits. Many...
During one particular war, the U.S. military was concerned about the nutrition of its recruits. Many did not have a sufficient number of teeth to chew the food provided to soldiers. As a result, it was likely that they would be undernourished and unable to fulfill their duties as soldiers. The requirements at that time specified that a recruit must have "at least four sound double teeth, one above and one below on each side of the mouth, and so...
The Reliable Housewares store manager wants to learn more about the purchasing behavior of its "credit"...
The Reliable Housewares store manager wants to learn more about the purchasing behavior of its "credit" customers. In fact, he is speculating about four specific cases shown below (a) through (d) and wants you to help him test their accuracy. The average annual income of credit customers is less than $48,000. The true population proportion of credit customers who live in an urban area exceeds 55%. The average number of years lived in the current home is less than 14...
Question 6 An investigator is looking at the relationship between periodontal disease and the onset of...
Question 6 An investigator is looking at the relationship between periodontal disease and the onset of hypertension. Suppose the investigator decides to look at height as a variable that may confound the relationship between exposure and case status in his study. After collecting information about the height of each participant, he assembles a database that approximates height with the normal distribution. A) Assuming the mean of the distribution is 176.2 cm with a standard deviation of 17.5 cm, what are...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT