4a The Dean of USD’s School of Business wants to estimate of the percentage of undergraduate students who do an internship. He wants to be 92% confident that the margin of error is less than 3 percent. Previous studies have shown this proportion to be around 66%..How large of a sample must he take?
496 |
||
764 |
||
564 |
||
655 |
||
None of the above |
Solution :
Given that,
= 66%=0.66
1 - = 1 - 0.66 = 0.34
margin of error = E = 3% = 0.03
At 92% confidence level the z is ,
Z/2 =1.75 ( Using z table
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.75/ 0.03)2 * 0.66*0.34
= 764
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