Question

The number of hours spent on social media during a one-week period was recorded for a random sample of 45 university students. For these 45 students, the mean number of social media hours was 12.52, with a standard deviation of 2.5. Researchers want to determine if the mean number of hours that all university students spend on social media each week is greater than 12, with a 5% level of significance.

What is the value of the t statistic?

What is the p value?

Answer 1

Solution :

= 12

=12.52

S =2.5

n = 45

This is the right tailed test .

The null and alternative hypothesis is ,

H0 :    = 12

Ha : > 12

Test statistic = t

= ( - ) / S / n

= (12.52- 12) / 2.5 / 45

= 1.395

Test statistic = t = 1.395

P-value =0.0850

= 0.05  

P-value ≥

0.0850 ≥ 0.05

Do not reject the null hypothesis .

There is insufficient evidence to suggest that