If n=29, ¯x(x-bar)=39, and s=5, find the margin of error at a
80% confidence level
Give your answer to two decimal places.
Solution :
Given that,
= 39
s =5
n = 29
Degrees of freedom = df = n - 1 =29 - 1 = 28
a ) At 80% confidence level the t is ,
= 1 - 80% = 1 - 0.80 = 0.20
/ 2= 0.10
t /2,df = t0.10,28 = 1.313 ( using student t table)
Margin of error = E = t/2,df * (s /n)
= 1.313 * (5 / 29)
E=1.22
Margin of error = E =1.22
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