Question

Two fair dice are rolled once. Find the probability that their sum is 8

Answer 1

When the two dice are thrown ,

(1 ,1) , (1,2)......(1,6),

(2,1) , (2, 2) ....(2,6),

(3,1) , (3,2) ......(3,6)

................................

...............................

(6,1) , (6,2) ........(6,6)

Total = 36

So a total of 8 can occur in follwing pairs:

(2 ,6) , (3,5) ,(4,4) , (5 , 3) ,(6, 2)

So there are 5 pairs of occurence of dice showing up faces when the serial number on the faces adds up 8, as against 36 possible pairs of numbers showing up.

So the probability of the event of showing the sum of the numbers on the face equal to 8 is 5/36 = 0.1388 = 0.14

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