Question

There is an average of four accidents per year at a particular intersection. What is the probability of more than one accident there next month? Hint: Use 1 month = 1/12 of a year to first get the number of accidents that are expected next month.

Answer #1

**ANSWER::**

Average rate = 4 per year

So, average rate = (4/12) per month = (1/3) per month.

This is Possion distribution because we have average value given.

Hence, probability of more than one accident in next month is
**0.0446.**

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