3)CC A sample of 219 women and a sample of 210 men was taken, and each person was asked what they considered to be the most credible medium for news (newspaper, television, internet). Here’s the data
Newspaper Television Internet TOTAL
Men 92 108 19 219
Women 97 81 32 210
TOTAL 189 189 51 429
a) Fill out the table of row proportions (each row should sum to 1
Newspaper Television Internet TOTAL
Men _____ _____ _____ 1.0
Women _____ _____ _____ 1.0
b) Perform the chi-square test of homogeneity to test the null hypothesis that women and men have similar preference patters.
X2 = _________ ; df = ___________ ; p-value = __________
Row proportions table:
Newspaper | Television | Internet | Total | ||
Men | 0.420091 | 0.493151 | 0.086758 | 1 | Rvalue/Rtotal |
Women | 0.461905 | 0.385714 | 0.152381 | 1 | |
Total | 0.440559 | 0.440559 | 0.118881 | 1 |
Chisquare Calculations:
O | Newspaper | Television | Internet | Total | |
Men | 92 | 108 | 19 | 219 | |
Women | 97 | 81 | 32 | 210 | |
Total | 189 | 189 | 51 | 429 | |
E | Newspaper | Television | Internet | Total | E=Rtotal*Ctotal/Grand total |
Men | 96.4825175 | 96.482517 | 26.03497 | 219 | |
Women | 92.5174825 | 92.517483 | 24.96503 | 210 | |
Total | 189 | 189 | 51 | 429 | |
X^2 | Newspaper | Television | Internet | Total | X^2 = (O-E)^2/E |
Men | 0.20825496 | 1.3748854 | 1.900933 | 3.484074 | |
Women | 0.21718017 | 1.433809 | 1.982402 | 3.633391 | |
Total | X^2 | 7.117465 |
X^2 = 7.1175
df = (r-1) * (c-1) = (2-1) * (3-1) = 2
P value = 0.0285 (Use X^2 table)
P value < 0.05, Reject H0
women and men have no similar preference patters.
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