Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.
11.8 | 6.3 | 7.1 | 9.7 | 6.5 | 8.1 | 6.8 |
8.7 | 6.8 | 7.0 | 7.8 | 7.4 | 10.7 | 9.0 |
7.7 | 5.4 | 6.3 | 7.9 | 7.7 | 7.0 | 8.7 |
7.3 | 11.6 | 11.3 | 7.2 | 8.2 | 9.7 |
a.)Calculate a point estimate of the population standard deviation
σ. [Hint: Σxi2 =
1862.79.]
b.)Calculate a point estimate of the population coefficient of variation σ/μ.
a. To find standard deviation we need to first find mean
Create the following table.
data | data-mean | (data - mean)2 |
11.8 | 3.663 | 13.417569 |
6.3 | -1.837 | 3.374569 |
7.1 | -1.037 | 1.075369 |
9.7 | 1.563 | 2.442969 |
6.5 | -1.637 | 2.679769 |
8.1 | -0.037 | 0.001369 |
6.8 | -1.337 | 1.787569 |
8.7 | 0.563 | 0.316969 |
6.8 | -1.337 | 1.787569 |
7.0 | -1.137 | 1.292769 |
7.8 | -0.337 | 0.113569 |
7.4 | -0.737 | 0.543169 |
10.7 | 2.563 | 6.568969 |
9.0 | 0.863 | 0.744769 |
7.7 | -0.437 | 0.190969 |
5.4 | -2.737 | 7.491169 |
6.3 | -1.837 | 3.374569 |
7.9 | -0.237 | 0.056169 |
7.7 | -0.437 | 0.190969 |
7.0 | -1.137 | 1.292769 |
8.7 | 0.563 | 0.316969 |
7.3 | -0.837 | 0.700569 |
11.6 | 3.463 | 11.992369 |
11.3 | 3.163 | 10.004569 |
7.2 | -0.937 | 0.877969 |
8.2 | 0.063 | 0.003969 |
9.7 | 1.563 | 2.442969 |
So
b. Point estimate of coefficient of variation is
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