Can you explain step by step. Can I resolve this problem on the calculator TI-84 Texas Instruments.
Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a 95% confidence interval estimate of the population percentage. Based on the result, does it appear that greater height is an advantage for presidential candidates? Why or why not?
PRESIDENT |
HEIGHT |
HEIGHT OPP |
|
---|---|---|---|
Taylor |
173 |
174 |
|
Pierce |
178 |
196 |
|
J. Q. Adams |
171 |
191 |
|
Carter |
177 |
183 |
|
Lincoln |
193 |
188 |
|
Jefferson |
189 |
170 |
|
G. W. BushG. |
183 |
185 |
|
Van Buren |
168 |
180 |
|
Harrison |
168 |
180 |
|
Buchanan |
183 |
175 |
|
Harrison |
173 |
168 |
|
Nixon |
182 |
180 |
|
Cleveland |
180 |
180 |
|
Wilson |
180 |
182 |
|
Johnson |
192 |
180 |
|
Hoover |
182 |
180 |
|
Polk |
173 |
185 |
|
J. Kennedy |
183 |
182 |
|
Coolidge |
178 |
180 |
|
Harding |
183 |
178 |
Construct a 95% confidence interval estimate of the percentage of presidents who were taller than their opponents.
----------%<p<----------%
(Round to one decimal place as needed.)
If greater height was an advantage, then taller candidates should have won--------------50% of the elections.
In this case, greater height --------------to be an advantage for presidential candidates because the confidence interval ------------include 50%.
A.
n = 20
No. of presidents who are taller than their opponents = 9 (I have not included the data where the president and the opponent were of the same height)
= 9/20
= 0.45
Confidence Interval:
i.e. [23.2%, 66.8%]
B.
more than
C.
is found
does include
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