Question

The following data from a random sample represents the average daily energy intake in kJ for...

The following data from a random sample represents the average daily energy intake in kJ for each of eleven healthy women:

5260    5470     5640     6180     6390     6515     6805     7515     7515    8230     8770     

Interest centred on comparing these data with an underlying mean daily energy intake of 7725 kJ This was the recommended daily intake. Departures from this mean in either direction were considered to be of interest. Assuming that the population is normal and the population variance is unknown. An appropriate two-tailed hypothesis test at the 5% level of significance was conducted. The null hypothesis is H0: m = 7725. What is the degree of freedom df in this problem?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Set up hypotheses for the following situations and explain your reasoning (One-tail or two-tailed? What are...
Set up hypotheses for the following situations and explain your reasoning (One-tail or two-tailed? What are your null and alternate hypotheses? Why?). Indicate whether a z-test or t-test would be recommended to evaluate the hypotheses. If a t-test is recommended, how many degrees of freedom should be used? The EU wants to examine statistics on refugees’ ages. Historically, the mean age of refugees arriving in Europe is 27.5 years old with a standard deviation of 3.1 years. In 2015, the...
Four students reported their study time and test score from a statistics course and their data...
Four students reported their study time and test score from a statistics course and their data have been converted into Z scores in the table below. What is Pearson's correlation coefficient from this data set? Group of answer choices a.)-.50 b.)-.25 c.).75 d.)-1.00 In what situation would a researcher use a  t-test used instead of a Z-test? Group of answer choices a.)When there is only one sample. b.)When the population standard deviation is unknown. c.)When the sample size is smaller than...
A random sample of 25 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 25 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 10.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown. No, the x distribution is skewed left.    No, the...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 8 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 7.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown. No, the x distribution is skewed left.     No, the...
Using the model proposed by Lafley and Charan, analyze how Apigee was able to drive innovation....
Using the model proposed by Lafley and Charan, analyze how Apigee was able to drive innovation. case:    W17400 APIGEE: PEOPLE MANAGEMENT PRACTICES AND THE CHALLENGE OF GROWTH Ranjeet Nambudiri, S. Ramnarayan, and Catherine Xavier wrote this case solely to provide material for class discussion. The authors do not intend to illustrate either effective or ineffective handling of a managerial situation. The authors may have disguised certain names and other identifying information to protect confidentiality. This publication may not be...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT