The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 3%, then the baby is premature. Find the length that separates premature babies from those who are not premature.
a. The probability that a pregnancy will last 308 days or longer is ?
b. Babies who are born on or before ____ days are considered premature.
Solution :
Given that ,
mean = = 268
standard deviation = = 15
(a)
P(x 308) = 1 - P(x 308)
= 1 - P((x - ) / (308 - 268) / 15)
= 1 - P(z 2.67)
= 1 - 0.9962
= 0.0038
Probability = 0.0038
(b)
P(Z < z) = 3%
P(Z < -1.88) = 0.03
z = -1.88
Using z-score formula,
x = z * +
x = -1.88 * 15 + 268 = 239.8
Babies who are born on or before 239.8 days are considered premature .
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