Ink cartridges of a certain brand are labelled to indicate that
they contain 12 ml.
Data has been collected about this brand. The corresponding sample
statistics are n
= 36 and x̄ = 12.19 ml.
If the cartridges are filled so that μ = 12.00 ml (as labelled) and
the population
standard deviation is σ = 0.11 ml (based on the observations),
determine the
probability that a sample of 36 cartridges will have a mean of
12.19 ml or greater.
Discuss about your results.
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We are given X : cartridges are filled with mean = 12.00 ml and standard deviation = 0.11 ml
If n = 36 , we asked probability that a sample of 36 cartridges will have mean of 12.19 ml or greater
P( xbar 12.19) = P[(xbar -)/(/√n)(12.19-)/(/√n)]
P(xbar 12.19) = P( Z 10.83)
= 1 - P( Z < 10.83(
P(xbar 12.19) = 1 - 1
P(xbar 12.19) = 0.0000
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