The length of salmon going into a particular river for spawning can be assumed to be normally distributed with the expected length µ = 90 cm and standard deviation σ = 10 cm. The lengths of different salmon are independent.
a) Calculate the probability that a salmon is over 100 cm.
Find the length a which is such that only 1% of the salmon is
longer than a cm.
Salmon fishermen in this river have a seasonal quota of 5 salmon.
Hanna is an avid salmon fisherman and fisherman until she has
filled the seasonal quota. Calculate the probability that the
average length of the 5 salmon is over 100 cm.
In a larger watercourse there are two salmon strains, strain A and
strain B. For strain A the expected length is µA = 90 and the
standard deviation σA = 10, while for strain B is µB = 96 and σB =
8. The lengths are as before independent and normally distributed.
.
It is further known that 70% of the salmon in the watercourse is
from strain A, while 30% is from strain B.
b) Calculate the probability that a salmon from the watercourse
is over 100 cm.
Calculate the probability that a salmon from strain A is longer
than a salmon from strain B.
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