Question

1. A cigarette manufacturer claims that one-eighth of the US adult population smokes cigarettes. In a...

1. A cigarette manufacturer claims that one-eighth of the US adult population smokes cigarettes. In a random sample of 100 adults, 5 are cigarette smokers. Test the manufacturer's claim at alpha= 0.05.  (critical values of z are ± 1.96).

2. A local telephone company claims that the average length of a phone call is 8 minutes. In a random sample of 58 phone calls, the sample mean was 7.8 minutes and the standard deviation was 0.5 minutes. Is there enough evidence to support this claim at alpha= 0.05? (critical values of z are ± 1.96).

Homework Answers

Answer #1

1)

Given:

P = 1/8 = 0.125,

Q =1-P = 1-0.125 = 0.875, n= 100,

Hypothesis:

(Claim)

Test statistic:

Conclusion:

| Test statistic (Z) | > Critical value, i.e. 2.27 > 1.96, That is Reject Ho at 5% level of signficance.

Ho is Rejected; you should conclude. " there is sufficient evidence to indicate that the manufactures claim is false."

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Cigarette Smoking A researcher found that a cigarette smoker smokes on average 31 cigarettes a day....
Cigarette Smoking A researcher found that a cigarette smoker smokes on average 31 cigarettes a day. She feels that this average is too high. She selected a random sample of 10 smokers and found that the mean number of cigarettes they smoked per day was 28. The sample standard deviation was 2.7. At a=0.05, is there enough evidence to support her claim? Assume that the population is approximately normally distributed. Use the P-value method and tables. Compute the test value....
A local telephone company claims that the average length of a phone call is 8 minutes...
A local telephone company claims that the average length of a phone call is 8 minutes in a random sample of 18 calls. The sample mean was 7.8 minutes and sample standard deviation was 0.5 minutes. Is there enough evidence to support the company’s claim at α=0.05.
The manufacturer of a new cigarette claims that the average tar content per cigarette is 10.0 mg
The manufacturer of a new cigarette claims that the average tar content per cigarette is 10.0 mg. The US Center for Smoking Research believes the tar content percigarette is greater than 10 mg and wishes to conduct a study to support their claim. Theytake a random sample of 25 cigarettes from the production line and find an average of 10.20mg of tar/cigarette and a standard deviation of .5 mg. Can the manufacturer’s claim berefuted at the 0.01 level of significance?A....
The manufacturer of an over-the-counter pain reliever claims that its product brings pain relief to headache...
The manufacturer of an over-the-counter pain reliever claims that its product brings pain relief to headache suffers in less than 3.5 minutes, on average. In order to be able to make this claim in its television advertisements, the manufacturer was required by a particular television network to present statistical evidence in support of the claim. The manufacturer reported that for a sample of 50 headache sufferers, the mean time to relief was 3.11 minutes and the standard deviation was 69.84...
Questions 1 – 3 are based on the following information. A tobacco cigarettes manufacturer claims that...
Questions 1 – 3 are based on the following information. A tobacco cigarettes manufacturer claims that the mean age of males and females starting to smoke cigarettes do not differ. A researcher would like to investigate the manufacturer’s claim and took random samples of 20 females and 30 males from normal populations and the descriptive statistics for the age of the respondents are tabulated below.   Use . Females (F) Males (M) Sample size () 20 30 Sample mean () 20...
1. A manufacturer claims that the mean lifetime of its fluorescent bulbs is 1500 hours. A...
1. A manufacturer claims that the mean lifetime of its fluorescent bulbs is 1500 hours. A homeowner selects 40 bulbs and finds the mean lifetime to be 1480 hours with a population standard deviation of 80 hours. Test the manufacturer's claim. Use alpha equal to 0.05. State the sample mean and the population standard deviation. 2. Using problem in number 1. Choose the correct hypotheses. 3. Using the problem in number 1. State the critical value(s). 4. Using the problem...
One urban affairs sociologist claims that the proportion, p , of adult residents of a particular...
One urban affairs sociologist claims that the proportion, p , of adult residents of a particular city who have been victimized by a criminal is at least 55% . A random sample of 245 adult residents of this city were questioned, and it was found that 119 of them had been victimized by a criminal. Based on these data, can we reject the sociologist's claim at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table...
This question has 4 parts 1 - 4 below. Enter your answer for each part. A...
This question has 4 parts 1 - 4 below. Enter your answer for each part. A random sample of 25 employees for the retailer showed a sample mean of 9.2 minutes and a standard deviation of 2 minutes. Assume that the time spent by employees on personal phone calls is normally distributed. Let μ denote the mean time spent by employees on personal phone calls. (1) Find the critical value from the table that is used to compute a 95%...
Suppose the coffee industry claimed that the average adult drinks 1.7 cups of coffee per day....
Suppose the coffee industry claimed that the average adult drinks 1.7 cups of coffee per day. To test this​ claim, a random sample of 50 adults was​ selected, and their average coffee consumption was found to be 1.9 cups per day. Assume the standard deviation of daily coffee consumption per day is 0.5 cups. Using alpha=0.01​, complete parts a and b below. a. Is the coffee​ industry's claim supported by this​ sample? Determine the null and alternative hypotheses. The​ z-test...
A laboratory claims that the mean sodium level, μ, of a healthy adult is 138 mEq...
A laboratory claims that the mean sodium level, μ, of a healthy adult is 138 mEq per liter of blood. To test this claim, a random sample of 43 adult patients is evaluated. The mean sodium level for the sample is 144 mEq per liter of blood. It is known that the population standard deviation of adult sodium levels is 14 mEq. Assume that the population is normally distributed. Can we conclude, at the 0.05 level of significance, that the...