A population is estimated to have a standard deviation of 8. We want to estimate the population mean within 2, with a 90% level of confidence.
How large a sample is required?
Solution :
Given that,
standard deviation = =8
Margin of error = E = 2
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
sample size = n = [Z/2* / E] 2
n = ( 1.645 * 8 / 2 )2
n =43
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